+0  
 
0
305
2
avatar

Find 4B if:

Ax-A+Bx+3B= 1

Guest Feb 2, 2016

Best Answer 

 #2
avatar+91049 
+5

I like this question - it is a little different.

 

Good try guest but I think all the Bs should be on the same side :/

 

Ax-A+Bx+3B= 1

 

Bx+3B = 1-Ax+A

B(x+3)=1-Ax+A

4B(x+3)=4(1-Ax+A)

 

\(4B=\frac{4(1-Ax+A)}{x+3}\\\)

Melody  Feb 2, 2016
Sort: 

2+0 Answers

 #1
avatar
+5

-4/3(Ax-A+Bx-1) =4B

Guest Feb 2, 2016
 #2
avatar+91049 
+5
Best Answer

I like this question - it is a little different.

 

Good try guest but I think all the Bs should be on the same side :/

 

Ax-A+Bx+3B= 1

 

Bx+3B = 1-Ax+A

B(x+3)=1-Ax+A

4B(x+3)=4(1-Ax+A)

 

\(4B=\frac{4(1-Ax+A)}{x+3}\\\)

Melody  Feb 2, 2016

15 Online Users

avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details