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find factor: x^2-2xy+y^2+3x-3y-4

Guest Dec 26, 2015

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 #1
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find factor: x^2-2xy+y^2+3x-3y-4

 

\(x^2-2xy+y^2+3x-3y-4\\ =(x^2-2xy+y^2)+(3x-3y)-4\\ =(x-y)^2+3(x-y)-4\\ \mbox{Let z=x-y}\\ =z^2+3z-4\\ =(z+4)(z-1)\\ =(x-y+4)(x-y-1) \)

Melody  Dec 26, 2015
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 #1
avatar+91045 
+15
Best Answer

find factor: x^2-2xy+y^2+3x-3y-4

 

\(x^2-2xy+y^2+3x-3y-4\\ =(x^2-2xy+y^2)+(3x-3y)-4\\ =(x-y)^2+3(x-y)-4\\ \mbox{Let z=x-y}\\ =z^2+3z-4\\ =(z+4)(z-1)\\ =(x-y+4)(x-y-1) \)

Melody  Dec 26, 2015
 #2
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Nice one, Melody.......I like how you did that.....!!!!

 

 

cool cool cool

CPhill  Dec 26, 2015
 #3
avatar+91045 
0

Thanks Chris,

It was a neat question.  :)

Melody  Dec 26, 2015

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