Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch side. A = sq. in.
Using Heron's formula where s = 9 ...... and a = b = c = the side lengths .....we have......
A = √[s(s -a)^3] = √[9*3^3] = √[9*27] = √[9*9*3] = √[81*3) = 9√3 sq. in.