find the exact value of the inverse of cos (-1/2)
for starters it is negative so it is the second quadrant.
Now I'll look for the first quad equivalent
This is just an equilateral triangle of side lenght 2 that has been split down the middle.
You can see that inverse cos (1/2) is 60degrees
The second quad equivalent 180-60=120°
$$cos^{-1}(-1/2)=120^0$$
find the exact value of the inverse of cos (-1/2)
for starters it is negative so it is the second quadrant.
Now I'll look for the first quad equivalent
This is just an equilateral triangle of side lenght 2 that has been split down the middle.
You can see that inverse cos (1/2) is 60degrees
The second quad equivalent 180-60=120°
$$cos^{-1}(-1/2)=120^0$$