Find the magnitude of the vector described below. Initial point: (–8, –9, –5)
Terminal point: (–2, –4, –3)
a. squareroot 65
b. 67
c. 2 squareroot 13
d. 13
e. squareroot 13
Find a unit vector in the direction of the vector described below. Initial point: (–8, 9, –1)
Terminal point: (1, 5, 0)
a. squareroot 14 (9,-4, 1)
b. (9, -4, 1)
c. 1/7 squareroot 2 (9, -4, 1)
d. 7 squareroot 2 (9, -4, 1)
e, 1/ squareroot 14 (9, -4, 1)
+118609 Find the magnitude of the vector described below. Initial point: (–8, –9, –5)
Terminal point: (–2, –4, –3)
\(d^2=(-2--8)^2+(-4--9)^2+(-3--5)^2\\ d^2=(-2+8)^2+(-4+9)^2+(-3+5)^2\\ d^2=(6)^2+(5)^2+(2)^2\\ d^2=36+25+4\\ d^2=65\\ d=\sqrt{65}\; units\\\)
Find a unit vector in the direction of the vector described below. Initial point: (–8, 9, –1)
Terminal point: (1, 5, 0)
This clip is quite good :0
https://www.youtube.com/watch?v=7lXqduogqhQ
\(\mbox{AB as an ordered triplet}\\ \bar{AB}=[(1--8),(5-9),(0--1)]=[9,-4,1]\\~\\ \mbox{Magnitude of AB}\\ |\bar{AB}|=\sqrt{9^2+(-4)^2+2^2}=\sqrt{81+16+1}=\sqrt{98}=7\sqrt2\\~\\ \mbox{Unit vector in the direction of AB}\\ \hat{\bar{AB}}=\frac{1}{7\sqrt2}[9,-4,1]\)
