Find the particular equation of the quadratic function containing (-2,-11), (4,13) and (6, 29)

The general equation for a quadratic is:  y = a*x² + b*x + c  where a, b and c are constants.  To find what they are here, substitute your three sets of (x, y) values into this general equation to give you three simultaneous equations for a, b and c:

 

 -11 = a*(-2)² + b*(-2) + c

 13 = a*4² + b*4 + c

 29 = a*6² + b*6 + c

 

or:

-11 = 4a - 2b + c

 13 = 16a +4b + c

 29 = 36a + 6b + c

 

Can you take it from here?

(You should find a = 1/2, b = 3, c = -7)

.