+1833 Five b***s are numbered 1 through 5 and placed in a bowl. Josh will randomly choose a ball from the bowl, look at its number and then put it back into the bowl. Then Josh will again randomly choose a ball from the bowl and look at its number. What is the probability that the product of the two numbers will be even and greater than 10? Express your answer as a common fraction.
+128731 There are 25 possible draws...the (1,1) (2,2) (3,3) (4,4) and (5,5) "draws" are indistinguishable as to order, but the other 10 listed can be "reversed" giving.... 5 + 2(10) = 25 total possible draws
(1,1) (1,2) (1,3) (1,4) (1,5)
(2,2) (2,3) (2,4) (2,5)
(3,3) (3,4) (3,5)
(4,4) (4,5)
(5,5)
Notice that only 5 out of 25 are even and greater than 10.....so the probabilty is 5/25 = 1/5
+128731 There are 25 possible draws...the (1,1) (2,2) (3,3) (4,4) and (5,5) "draws" are indistinguishable as to order, but the other 10 listed can be "reversed" giving.... 5 + 2(10) = 25 total possible draws
(1,1) (1,2) (1,3) (1,4) (1,5)
(2,2) (2,3) (2,4) (2,5)
(3,3) (3,4) (3,5)
(4,4) (4,5)
(5,5)
Notice that only 5 out of 25 are even and greater than 10.....so the probabilty is 5/25 = 1/5
