For this equation: 3y + 6x = -24
a. Find the slope: ___________
b. Find the Y intercept: ______________
c. Graph the line.
+23247 The slope-intercept form for a straight line is: y = mx + b
where m is the slope and b is the y-intercept.
So, solve the equation for y (get y alone on one side):
3y + 6x = -24
subtract 6x from both sides:
3y = -6x - 24
divide both sides by 3:
y = -2x - 8
m = -2 <--- slope
b = -8 <--- y-intercept
To graph the line, place a dot on the y-axis at -8; then find more points by using the slope of -2,
which means move to the right one mark and down two marks, place a dot there, move to the right another mark and down another two marks and place a dot there ... Connect all the dots with a straight line.
+23247 The slope-intercept form for a straight line is: y = mx + b
where m is the slope and b is the y-intercept.
So, solve the equation for y (get y alone on one side):
3y + 6x = -24
subtract 6x from both sides:
3y = -6x - 24
divide both sides by 3:
y = -2x - 8
m = -2 <--- slope
b = -8 <--- y-intercept
To graph the line, place a dot on the y-axis at -8; then find more points by using the slope of -2,
which means move to the right one mark and down two marks, place a dot there, move to the right another mark and down another two marks and place a dot there ... Connect all the dots with a straight line.
