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general solution for sin2x + 2 cos x = 0

nlbradshaw0430  Apr 13, 2017
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sin2x + 2 cos x = 0

 

2sinxcosx + 2cosx  = 0      divide through by 2

 

sinxcosx + cosx  =  0        factor

 

cosx (sinx + 1)  = 0

 

So either

 

cosx  = 0    and this happens at  pi/2  + pi*n     where n is an integer

 

Or

 

sin x  +  1  = 0

 

sin x  =  - 1       and this happens at  3pi /2  + 2pi*n   where n is an integer

 

 

 

cool cool cool

CPhill  Apr 13, 2017
edited by CPhill  Apr 13, 2017

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