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Give the coordinates of the circle's center and its radius.

(x−1)^2 +(y+8)^2 =16

 

a. (-1,8);r=4

b. (1,-8);r=16

c. (1,-8);r=4

d. (-1,8);r=16

e. none of these

 

 

 

 

Find the vertex and focus of the parabola.

(y-2)^2 +16(x-3)=0

 

a. vertex: (3,2)     focus: (3,-2)

b. vertex: (-3,-2)     focus: (-3,-18)

c. vertex: (-3,-2)     focus: (-3, 14)

d. vertex: (3,2)     focus: (-1,2)

e. vertex: (-3,-2)     focus: (-7,-2)

 Aug 27, 2016
 #1
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(x−1)^2 +(y+8)^2 =16

 

Center=  ( 1, -8)   Radius =  4   →    'd"

 

 

 

(y-2)^2 +16(x-3)=0      put into this form

 

(x - h)   =  (1/[4p] ) (y -  k)^2       where (h,k) is the vertex  and the focus is given by [h + p , k]

 

(x - 3)  =  - (1/16)(y -2)^2

 

The vertex is (3, 2)       this parabola opens to the left, and we can find p thusly :

 

- [1/16 ] = [1/ (4p) =    so  p    =  - 4   

 

So the focus  = (3  + (- 4 ) ,  2 )  =  ( -1, 2)

 

"d"  is the correct choice

 

 

cool cool cool

 Aug 27, 2016

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