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On the merry-go-round, each horse moves up and down five times in one complete revolution. The up- and - down motion of each horse can be modeled by the function h(t) = 25cos(5ϴ), where h is the horse's displacement in centimetre from its centre and ϴ is the rotation angle of the merry-go-round. Assume the rides begins when ϴ=0 degrees for a given horse.

A) At what rotation angles will the horse be displaced 15 cm above its original position in one revolution? 

B) At what rotation angles will the horse be displaced 20 cm below its original position in one revolution?

C) How long will it take for one complete revolution if the carousel rotates at a speed of 24degrees/s?

 Jan 17, 2017

Best Answer 

 #7
avatar+36919 
+5

I see now.....they start at the high point when theta = 0  originally     so they will be at 25 above center and never reach 15cm above that!      d'Oh!

 Jan 17, 2017
 #1
avatar+36919 
0

A:   15cm = 25cos(5t)      t= theta

     15/25 = cos 5t

     Arcos (15/25) = 5t      t= .185 R =10.62 degrees

 

B  -20 = 25 cos(5t)

    -20/25 = cos 5t

  Arcos (-20/25) = 5t    t = .4996 R   28.62 degrees

 

C   360 degrees/ (24 degrees/sec)  = 15 seconds

 Jan 17, 2017
 #2
avatar+36919 
0


Ooops sorry....I gave onlt the FIRST position of those displacements.....back in a few

ElectricPavlov  Jan 17, 2017
 #3
avatar+36919 
0

A   5 times every rotation is every 72 degrees

   10.62 + 72 =   82.62        154.62     226.62    298.62   370.62

   BUT, they also will be displaced 15 cm on the way DOWN for another 5 times each rotation

     arcos(-15/25) = 5t = .44 R    25.37 degrees  97.37   169.37  2.41.37  313.37  degrees

 

 

(I think !)

ElectricPavlov  Jan 17, 2017
 #5
avatar+36919 
0

Disregard all of this......time to rethink my answers !!!!!

ElectricPavlov  Jan 17, 2017
 #4
avatar+128731 
0

A) At what rotation angles will the horse be displaced 15 cm above its original position in one revolution? 

 

The horse is at its max height [25cm] when the ride starts  [at θ  = 0] ......thus, it never rises15 cm above its original poisition.......

 

 

B) At what rotation angles will the horse be displaced 20 cm below its original position in one revolution?

 

The height at those angles will be 5cm....so we have

 

5  = 25cos(5θ)  

 

Have a look at the graph here  [in degrees].......https://www.desmos.com/calculator/pusq0nejlq

 

The graph shows that this height occurs 10 times in one revolution

 

 

C) How long will it take for one complete revolution if the carousel rotates at a speed of 24degrees/s?

 

360 / 24  = 15 seconds

 

 

 

cool cool cool

 Jan 17, 2017
 #6
avatar+36919 
0

NOW I am more confused     h = 25 cos(5theta)  is it's position from its CENTER......

 Is that what you assumed , Chris??

ElectricPavlov  Jan 17, 2017
 #7
avatar+36919 
+5
Best Answer

I see now.....they start at the high point when theta = 0  originally     so they will be at 25 above center and never reach 15cm above that!      d'Oh!

ElectricPavlov  Jan 17, 2017
 #9
avatar+128731 
0

Whatever....this question is confusing......!!!!

 

 

 

cool cool cool

 Jan 17, 2017
 #10
avatar+36919 
+5

I think, as the question is written......you're answers are correct.....AND you are correct again when you say the Q is confusing !   

ElectricPavlov  Jan 17, 2017

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