Why when I draw the graph for sqrt(x) it appears to have values for x<0?
If y=sqrt(x) and y is in the real number system then x cannot be less then x
That is, you cannot find the squareroot of a negative number
Here is the graph.
https://www.desmos.com/calculator/zeallc6van
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Where did you graph it to get results of x<0 ??
Thanks Heureka,
However,
I do not think any of these graphs are
y=sqrt(x) when x is negative.
"Why when I draw the graph for sqrt(x) it appears to have values for x<0?"
You don't show what your graph looks like. If it looks like the one below then you've plotted the square root of the absolute value of x:
.
It looks like this when I use web2.0calc.com to draw it:
http://i64.tinypic.com/2ihqull.jpg