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Why when I draw the graph for sqrt(x) it appears to have values for x<0?

 Jul 21, 2016

Best Answer 

 #7
avatar+33616 
+10

Clearly a bug in the web2.0calc graphing as it has drawn the square root of the absolute value of x.

 Jul 22, 2016
 #1
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0

How are you drawing this graph? By hand, graphing calculator, etc.?

 Jul 21, 2016
 #2
avatar+118609 
0

Why when I draw the graph for sqrt(x) it appears to have values for x<0?

 

 

If y=sqrt(x)  and y is in the real number system then x cannot be less then x

 

That is, you cannot find the squareroot of a negative number

 

Here is the graph.

 

https://www.desmos.com/calculator/zeallc6van

 

-----------------------------------------------------------------

 

Where did you graph it to get results of x<0 ??

 Jul 22, 2016
 #3
avatar+26367 
+5

Why when I draw the graph for sqrt(x) it appears to have values for x<0?

 

 

laugh

 Jul 22, 2016
 #4
avatar+118609 
0

Thanks Heureka,

 

However,

 

  I do not think any of these graphs are 

 

y=sqrt(x) when x is negative.

 Jul 22, 2016
 #5
avatar+33616 
+5

"Why when I draw the graph for sqrt(x) it appears to have values for x<0?"

 

You don't show what your graph looks like.  If it looks like the one below then you've plotted the square root of the absolute value of x:

 

sqrt(abs(x))

.

 Jul 22, 2016
 #6
avatar
+5

It looks like this when I use web2.0calc.com to draw it:

http://i64.tinypic.com/2ihqull.jpg

 Jul 22, 2016
edited by Guest  Jul 22, 2016
 #7
avatar+33616 
+10
Best Answer

Clearly a bug in the web2.0calc graphing as it has drawn the square root of the absolute value of x.

Alan  Jul 22, 2016
 #8
avatar
0

Ok. Thank you all!

 Jul 22, 2016
 #9
avatar+118609 
+5

 

I suggest that you use Desmos for you graphs.  :)

 

https://www.desmos.com/calculator

 Jul 22, 2016

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