+0

# help me to solve this please

0
180
1

$${\frac{{\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{8}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{6}}}}\right)}}{{{\mathtt{16}}}^{\left({\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)}}}$$

Guest Feb 28, 2015

#1
+91458
+5

Mmm

Lets see.

$$\\\dfrac{4\times 2^{1/4}\times8^{1/6}}{16^{3/4}}\\\\\\ =\dfrac{2^2\times 2^{1/4}\times(2^3)^{1/6}}{(2^4)^{3/4}}\\\\\\ =\dfrac{2^2\times 2^{1/4}\times 2^{3/6}}{2^{12/4}}\\\\\\ =\dfrac{2^2\times 2^{0.25}\times 2^{0.5}}{2^{3}}\\\\ =2^{2+0.25+0.5-3}\\\\ =2^{-0.25}\\\\ =\frac{1}{2^{1/4}}\\\\ =\frac{1}{\sqrt[4]{2}}$$

Melody  Feb 28, 2015
Sort:

#1
+91458
+5

Mmm

Lets see.

$$\\\dfrac{4\times 2^{1/4}\times8^{1/6}}{16^{3/4}}\\\\\\ =\dfrac{2^2\times 2^{1/4}\times(2^3)^{1/6}}{(2^4)^{3/4}}\\\\\\ =\dfrac{2^2\times 2^{1/4}\times 2^{3/6}}{2^{12/4}}\\\\\\ =\dfrac{2^2\times 2^{0.25}\times 2^{0.5}}{2^{3}}\\\\ =2^{2+0.25+0.5-3}\\\\ =2^{-0.25}\\\\ =\frac{1}{2^{1/4}}\\\\ =\frac{1}{\sqrt[4]{2}}$$

Melody  Feb 28, 2015

### 10 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details