I assume this might be......
log2(x^2 + 2x) = 3 if so, we can write
2^3 = x^2 + 2x → 8 = x^2 + 2x rearrange
x^2 + 2x - 8 = 0 factor
(x + 4) (x - 2) = 0 and setting each factor to 0, we have that x = -4 and x = 2
We must reject x = 2, because it leads to taking a log of 0 in the original problem, and this is undefined
x = -4 is the only solution
I assume this might be......
log2(x^2 + 2x) = 3 if so, we can write
2^3 = x^2 + 2x → 8 = x^2 + 2x rearrange
x^2 + 2x - 8 = 0 factor
(x + 4) (x - 2) = 0 and setting each factor to 0, we have that x = -4 and x = 2
We must reject x = 2, because it leads to taking a log of 0 in the original problem, and this is undefined
x = -4 is the only solution