The exponential function
N = 3.93 × 1.34 ^d gives the approximate U.S. population, in millions, d decades after 1790. (The formula is valid only up to 1860.)
Find a formula that gives the U.S. population c centuries after 1790. (Assume that the original formula is valid over several centuries.)
The exponential function
N = 3.93 × 1.34 ^d gives the approximate U.S. population, in millions, d decades after 1790. (The formula is valid only up to 1860.)
Find a formula that gives the U.S. population c centuries after 1790. (Assume that the original formula is valid over several centuries.)
3.93×1.34d=3.93×a0.1d1.34d=a0.1dlog(1.34d)=log(a0.1d)d∗log(1.34)=0.1d∗log(a)log(1.34)=0.1∗log(a)10log(1.34)=log(a)log(a)=10log(1.34)10log(a)=1010∗log(1.34)a=1010∗log(1.34)a≈18.6659(4dp)
N = 3.93 × 1.34 ^d
N = 3.93 × 18.6659 ^C C for century
check after 1/2 cnetury
N = 3.93 × 1.34 ^5 =16.979
N = 3.93 × 18.6659 ^0.5 = 16.979
after 5 centuries
N = 3.93 × 1.34 ^50 = 8 904 970
N = 3.93 × 18.6659 ^5 = 8 905 067 difference due to rounding
The exponential function
N = 3.93 × 1.34 ^d gives the approximate U.S. population, in millions, d decades after 1790. (The formula is valid only up to 1860.)
Find a formula that gives the U.S. population c centuries after 1790. (Assume that the original formula is valid over several centuries.)
3.93×1.34d=3.93×a0.1d1.34d=a0.1dlog(1.34d)=log(a0.1d)d∗log(1.34)=0.1d∗log(a)log(1.34)=0.1∗log(a)10log(1.34)=log(a)log(a)=10log(1.34)10log(a)=1010∗log(1.34)a=1010∗log(1.34)a≈18.6659(4dp)
N = 3.93 × 1.34 ^d
N = 3.93 × 18.6659 ^C C for century
check after 1/2 cnetury
N = 3.93 × 1.34 ^5 =16.979
N = 3.93 × 18.6659 ^0.5 = 16.979
after 5 centuries
N = 3.93 × 1.34 ^50 = 8 904 970
N = 3.93 × 18.6659 ^5 = 8 905 067 difference due to rounding