($${\frac{{\left({{\mathtt{w}}}^{-{\mathtt{2}}}\right)}^{{\mathtt{3}}}}{{{\mathtt{W}}}^{-{\mathtt{8}}}}}$$ How do I solve this?
w^(-2*3)/w^-8
w^-6/w^-8
w^(-6+8)
w^2
