As a scuba diver descends into deeper water, the
pressure of the water on the diver's body steadily increases.
The pressure at the surface of the water is 2120 pounds per square
foot (lb/ft2).The pressure increases at a rate of 64 pounds per square
foot for each foot the diver descends. Find the depth at which a
diver experiences a pressure of 7240 pounds per square foot.
+23247 Since the pressure increases at the rate of 64 pounds/sq ft for each foot of descent,
the amount of increase can be written as 64 · n where n represents the number of feet of descent.
Initial Pressure + Increased Pressure Due To Depth = Final Pressure
2120 lb/ft² + (64 lb/ft²/ft) · (n ft) = 7240 lb/ft²
(64 lb/ft²) · n ft = 5120 lb/ft²
n = 80 ft
+23247 Since the pressure increases at the rate of 64 pounds/sq ft for each foot of descent,
the amount of increase can be written as 64 · n where n represents the number of feet of descent.
Initial Pressure + Increased Pressure Due To Depth = Final Pressure
2120 lb/ft² + (64 lb/ft²/ft) · (n ft) = 7240 lb/ft²
(64 lb/ft²) · n ft = 5120 lb/ft²
n = 80 ft
