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A researcher conducted an Internet survey of 500 students at a particular college to estimate the average amount of money students spend on groceries per week. The data are normally distributed, with the highest weekly amount being $200 and the lowest weekly amount being $75. The sample mean is $140. What is the margin of error (ME), rounded to the nearest hundredth, for this college? {nl} {nl} Hint:  where SD is the standard deviation, XH is the high value, and XL is the low value {nl} {nl} Hint:  where SD is the standard deviation and N is the sample size.

 

A. ME = ±$2.15

B. ME = ±$931.69

C. ME = ±$1.86

D. ME = ±$1.80

 May 3, 2016
edited by Guest  May 3, 2016
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Its C

 May 10, 2022

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