how do you find the vertex of y=x^2-x-2
y=x^2-x-2
The x coordinate of the vertex = -b / 2a where b = -1 and a = 1 .....so....we have...
x = -b / 2a = 1/ 2(1) = 1/2
And the y coordinate =
(1/2)^2 - (1/2) - 2 = 1/4 - 1.2 - 2 = -1/4 - 2 = -9/4
So.....the vertex = ( 1/2, -9/4 )
