Any help would be appreciated!
solve for y
y=18.5+6sin((9(pi/12)) - (10(pi/12)))
I am jut going to REDO it here :))
$$\\y=18.5+6sin((9(\pi/12)) - (10(\pi/12)))\\\\
y=18.5+6sin(9\pi/12 - 10\pi/12)))\\\\
y=18.5+6sin(-\pi/12)))\\\\
$ 4th quad so neg$\\\\
y=18.5-6sin(\pi/12)))\\\\
y=18.5-6sin(15^0)\\\\
y=18.5-6sin(45-30)\\\\
y=18.5-6[sin45cos30-cos45sin30]\\\\
y=18.5-6[\frac{1}{\sqrt2}*\frac{\sqrt3}{2}-\frac{1}{\sqrt2}*\frac{1}{2}]\\\\$$
$$\\y=18.5-6[\frac{\sqrt3}{2\sqrt2}-\frac{1}{2\sqrt2}]\\\\
y=18.5-6[\frac{\sqrt6}{4}-\frac{\sqrt2}{4}]\\\\
y=18.5-3[\frac{\sqrt6}{2}-\frac{\sqrt2}{2}]\\\\
y=\frac{37-3\sqrt6+3\sqrt2}{2}\\\\$$
Ok NOW our answers are the same :))
Thiere is a mistake in this one so you had best ignore it ://
$$\\y=18.5+6sin((9(\pi/12)) - (10(\pi/12)))\\\\
y=18.5+6sin(3\pi/4) - (5\pi/6)\\\\
y=18.5+6sin(3\pi/4) - (5\pi/6)\\\\
$second quad so the sine is positive$\\\\
y=18.5+6sin(\pi-\3pi/4) - (5\pi/6)\\\\
y=18.5+6sin(\pi/4) - (5\pi/6)\\\\
y=18.5+6*\frac{1}{\sqrt2} - (5\pi/6)\\\\
y=18.5+6*\frac{1*\sqrt2}{\sqrt2*\sqrt2} - (5\pi/6)\\\\
y=18.5+6*\frac{\sqrt2}{2} - (5\pi/6)\\\\
y=18.5+3\sqrt2 - \frac{5\pi}{6}\\\\$$
Hello,melody and anon!
I think melody made a mistake.(9pi/12-10pi/12 is in inside of the parentheses)
y=18.5+6sin((9(pi/12)) - (10(pi/12)))
y=18.5+6sin(9pi/12-10pi/12)
y=18.5+6sin(-pi/12)
y=18.5-6sin(pi/12)
y=18.5-6sin(pi/4-pi/6)
$${\mathtt{y}} = {\mathtt{18.5}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left(\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{4}}}}\right)}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}\right)}{\mathtt{\,-\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{4}}}}\right)}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}\right)}\right)$$
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{4}}}}\right)} = {\frac{{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}$$ $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}\right)} = {\frac{{\sqrt{{\mathtt{3}}}}}{{\mathtt{2}}}}$$ $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{4}}}}\right)} = {\frac{{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}$$ $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}\right)} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$
$${\mathtt{y}} = {\mathtt{18.5}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left({\frac{{\sqrt{{\mathtt{6}}}}}{{\mathtt{4}}}}{\mathtt{\,-\,}}{\frac{{\sqrt{{\mathtt{2}}}}}{{\mathtt{4}}}}\right) = {\mathtt{18.5}}{\mathtt{\,-\,}}{\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{6}}}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}$$
I am jut going to REDO it here :))
$$\\y=18.5+6sin((9(\pi/12)) - (10(\pi/12)))\\\\
y=18.5+6sin(9\pi/12 - 10\pi/12)))\\\\
y=18.5+6sin(-\pi/12)))\\\\
$ 4th quad so neg$\\\\
y=18.5-6sin(\pi/12)))\\\\
y=18.5-6sin(15^0)\\\\
y=18.5-6sin(45-30)\\\\
y=18.5-6[sin45cos30-cos45sin30]\\\\
y=18.5-6[\frac{1}{\sqrt2}*\frac{\sqrt3}{2}-\frac{1}{\sqrt2}*\frac{1}{2}]\\\\$$
$$\\y=18.5-6[\frac{\sqrt3}{2\sqrt2}-\frac{1}{2\sqrt2}]\\\\
y=18.5-6[\frac{\sqrt6}{4}-\frac{\sqrt2}{4}]\\\\
y=18.5-3[\frac{\sqrt6}{2}-\frac{\sqrt2}{2}]\\\\
y=\frac{37-3\sqrt6+3\sqrt2}{2}\\\\$$
Ok NOW our answers are the same :))