+5265 If the area of a nickel is 353 mm2, Tell about how many nickels would cover a square tabletop that measures 1 square meter.
Then, tell the cost of the coins. (Nickels=5 cents.)
+36916 1 sq meter is 1000mm x 1000 mm
1000 x 1000 / 353 = 2832.86 (if they were SQUARE and not round)
diameter of a nickel is 353/pi = r^2 r = 10.6mm Diameter is 21.2 1000/ (21.2) = 47 nickles to a side 47 x 47 = 2209 nickles ($110.45)
+36916 1 sq meter is 1000mm x 1000 mm
1000 x 1000 / 353 = 2832.86 (if they were SQUARE and not round)
diameter of a nickel is 353/pi = r^2 r = 10.6mm Diameter is 21.2 1000/ (21.2) = 47 nickles to a side 47 x 47 = 2209 nickles ($110.45)
1 meter=1,000mm
1 square meter=1,000 x 1,000=1,000,000mm^2
1,000,000 / 353 =2,833 nickels in 1 square meter.
2,833 x .05 =$141.65 Total value of 2,833 nickels.
+36916 ...as an addendum to EP above..... If you 'overlap' (more correctly: 'OFFSET') the nickles row by row, you can get more of them on the table top, but STILL not 2832 of them but MORE than 2209 of them....not sure how to calculate this though.....will se if I can come up with a method.....
+36916 OK.....did a little math and drawing pictures and came up with 50 rows of nickles (actually 50.55) to a side if you offset the rows so the nickles stack more closely
Ignoring the .55 nicklle in the solution
50 x 50 = 2500 nickles maximum = $125.00
