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Solve for \$a\$ in terms of \$b\$ and \$c\$, assuming \$b\neq 3\$: \[ab  = 3a + 2b + c.\]

Guest Oct 16, 2017
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ab  =  3a + 2b + c

ab - 3a  =  2b + c

a [ b - 3]  = 2b + c

a =  [ 2b + c ] / [ b - 3]

CPhill  Oct 16, 2017

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