+0

# HELP!!!

+1
79
1
+318

A)State an interval in which the x -coordinate of the maximum turning point on the graph of y=−x(x+2)(x−3)  must lie.

B)Use a numerical method to zoom in on this interval and hence estimate the position of the maximum turning point of the graph with the x -coordinate correct to 1 decimal place.

Sort:

#1
+75344
+2

y  = -x ( x + 2) (x - 3)

The zeroes are  at x = -2, x = 0  and x  = 3

From (-inf, -2) the graph will be > 0

From (-2, 0) the graph will be < 0

From (0, 3) the graph will be > 0

And from (3, inf) the graph will be < 0

A minimum turning point will occur on ( -2, 0)  and a maximum turning point will occur between (0, 3)

We could use Calculus to find these turning points but look at the graph here : https://www.desmos.com/calculator/1qkjsbo1r3

It shows that the max turning point occurs at x ≈ 1.786  ≈ 1.8

CPhill  May 24, 2017
edited by CPhill  May 24, 2017

### 8 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details