what do you do when you get this when completing the square of a quadratic equation?
\(x = \frac{2-2\sqrt{3}}{2}\)
do you remove the zero? or not? please help!
I think...your radical needs a ± sign in front of it..
\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\) We can reduce this fraction by 2 .
So, your exact solutions are:
x = 1 + √3 and x = 1 - √3
We can get approximate solutions by putting it into a calculator:
x ≈ 2.732 and x ≈ -0.732
These should be the x values that cause the y to equal zero.
Does that help any? I don't know what you mean by " remove the zero " .
I think...your radical needs a ± sign in front of it..
\(x=\frac{2\pm2\sqrt3}{2} \\~\\ x=\frac{2(1\pm\sqrt3)}{2} \\~\\ x=1\pm\sqrt3\) We can reduce this fraction by 2 .
So, your exact solutions are:
x = 1 + √3 and x = 1 - √3
We can get approximate solutions by putting it into a calculator:
x ≈ 2.732 and x ≈ -0.732
These should be the x values that cause the y to equal zero.
Does that help any? I don't know what you mean by " remove the zero " .