How did they factor this trig equation?

So the equation is this:

\(9sec^2\theta tan\theta - 12tan\theta=0\)

 

And somehow it factors out to this:

 

\(3tan\theta (3sec^2\theta - 4)=0\)

 

Can someone explain to me the factoring steps? I'm very lost
Thanks!
P.S. I hate pearson my math lab with a burning passion