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So the equation is this:


\(9sec^2\theta tan\theta - 12tan\theta=0\)

 

And somehow it factors out to this:

 

\(3tan\theta (3sec^2\theta - 4)=0\)

 

Can someone explain to me the factoring steps? I'm very lost
Thanks!
P.S. I hate pearson my math lab with a burning passion

CurlyFry  Apr 16, 2017
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2+0 Answers

 #1
avatar+77125 
+3

9sec^2 (x)  tan(x)   -  12tan (x)   = 0       re-write as

 

9tan (x) sec^2 (x)  - 12 tan (x)   =   0

 

Factor out the greatest common factor,   3tan(x)

 

3tan (x)  [ 3 sec^2 (x)  - 4  ]  = 0

 

 

cool cool cool

CPhill  Apr 16, 2017
 #2
avatar+14 
+2

Ohhh duh, thanks so much :)

CurlyFry  Apr 16, 2017

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