how do 2 negative integers divided, equal a positive number

Sorry.     

ok

I have shown you that 

-2*4   =-8

now if I divide both sides by -2,  I get

$$\\\frac{-2*4}{-2}=\frac{-8}{-2}\\\\
4=\frac{-8}{-2}\\\\
\frac{-8}{-2}=4$$

therefore a negative divided by a negative = a positive

Because that's the way it is. See? That is what happens.$${\frac{\left(-{\mathtt{45}}\right)}{\left(-{\mathtt{54}}\right)}} = {\frac{{\mathtt{5}}}{{\mathtt{6}}}} = {\mathtt{0.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

Well I can demonstrate with a pattern

4*3    =12

4*2     =8

4*1     =4

4*0     =0

4*-1    =-4

4*-2    =-8

Can you see that the pattern shows that a pos * a neg = a neg  ?

Now i will swap it around

-2*4   =-8

-2*3  =-6

-2*2  =-4

-2*1  =-2

-2*0  =0

-2*-1  =+2

-2*-2  =+4

-2*-3   =+6

Can you see how the pattern shows that a neg * a neg = a pos  ?

there are other ways to show this as  well.  One of the other answerers may show you another way. :)

Yes, Melody. Neat. But the question was about division!