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how do i find out the value of a in the equation 6 = a(1-5)(1+3)

 Oct 30, 2014

Best Answer 

 #2
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+5

Well, first you should finish up the calculations within the brackets:

6=a(1-5)(1+3)  becomes  6=a(-4)(4)

Then, simplify by multiplying the bracketed number together:

6=a(-4)(4) becomes 6=a(-16)

Finally, divide -16 from both sides to isolate a:

6=a(-16) becomes 6/-16=(a*-16)/-16, the -16's on the right side cancel

to leave isolated and equal to 6/-16 or -3/8 or -0.375, and yer done!

 Oct 30, 2014
 #1
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+5

6 = a(1-5)(1+3)    simplify

6 = a(-4)(4)

6 = a (-16)     divide both sides by -16

-6/16 = a = -3/8

 

 Oct 30, 2014
 #2
avatar
+5
Best Answer

Well, first you should finish up the calculations within the brackets:

6=a(1-5)(1+3)  becomes  6=a(-4)(4)

Then, simplify by multiplying the bracketed number together:

6=a(-4)(4) becomes 6=a(-16)

Finally, divide -16 from both sides to isolate a:

6=a(-16) becomes 6/-16=(a*-16)/-16, the -16's on the right side cancel

to leave isolated and equal to 6/-16 or -3/8 or -0.375, and yer done!

Guest Oct 30, 2014

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