How do I solve this? ALEGBRA

Question

0

625

3

+117

$$\frac{4x^2-9}{2x+5}:\frac{(2x-3)^2}{4x^2-25}$$

Namodesto Nov 20, 2014

+23245

+10

Best Answer

Since it is a division problem, multiply by the reciprocal:

Factored: [ (2x - 3)(2x + 3) ] / (2x + 5) · [ (2x + 5)(2x - 5) ] / [ (2x - 3)(2x - 3) ]

Numerator: (2x - 3)(2x + 3)(2x + 5)(2x - 5)

Denominator: (2x + 5)(2x - 3)(2x - 3)

Cancel: [ (2x + 3)(2x - 5) ] / (2x - 3)

geno3141 Nov 20, 2014

geno3141 · Answer 1 · 2014-11-20T09:54:58

Since it is a division problem, multiply by the reciprocal:

Factored: [ (2x - 3)(2x + 3) ] / (2x + 5) · [ (2x + 5)(2x - 5) ] / [ (2x - 3)(2x - 3) ]

Numerator: (2x - 3)(2x + 3)(2x + 5)(2x - 5)

Denominator: (2x + 5)(2x - 3)(2x - 3)

Cancel: [ (2x + 3)(2x - 5) ] / (2x - 3)

geno3141 · Answer 2 · 2014-11-20T09:45:12

Nothing will cancel; is there a division sign between them?

Namodesto · Answer 3 · 2014-11-20T09:48:45

yes, i forgot to put it in my equation