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how do i solve this equation? exp(ln(0.81)/2 I always get other number than 0.9

 May 3, 2016
 #1
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I assume this is :

 

e^[ln (0.81) /  2 ]  .....if so, we have

 

e^[ (1/2) ln (0.81) ]  =

 

e^[ ln (0.81)^(1/2) ] =

 

Remember that  ......  e^[ln a]   = a

 

(0.81)^(1/2)  =

 

√[ 0.81]  = 

 

√ [ 81/100]  =

 

9/10  =  0.9

 

 

cool cool cool

 May 3, 2016
 #2
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Thanks a lot!!!!

 May 3, 2016

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