How do you do (9+3)-3x+34^2-8(2-9)=38x?

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How do you do (9+3)-3x+34^2-8(2-9)=38x?

Guest Apr 1, 2015

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Best Answer

+128707

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(9+3)-3x+34^2-8(2-9)=38x simplify

12 - 3x + 34^2 - 8(-7) = 38x

12 - 3x + 1156 + 56 = 38x

1223 - 3x = 38x add 3 x to both sides

1224 = 41x divide both sides by 41

x = about 29.8536585365853659

CPhill Apr 1, 2015

1⁺⁰ Answers

+128707

+5

Best Answer

(9+3)-3x+34^2-8(2-9)=38x simplify

12 - 3x + 34^2 - 8(-7) = 38x

12 - 3x + 1156 + 56 = 38x

1223 - 3x = 38x add 3 x to both sides

1224 = 41x divide both sides by 41

x = about 29.8536585365853659

CPhill Apr 1, 2015

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