How do you get rid of an exponent in an equation?

Question

0

1155

2

Guest Apr 24, 2015

+118609

+5

Best Answer

What like

$$5^x=7\\
log5^x=log7\\
xlog5=log7\\
x=log7 \div log 5\\$$

$${\frac{{log}_{10}\left({\mathtt{7}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} = {\mathtt{1.209\: \!061\: \!955\: \!122\: \!167\: \!3}}$$

Melody Apr 24, 2015

Melody · Answer 1 · 2015-04-24T05:58:10

What like

$$5^x=7\\
log5^x=log7\\
xlog5=log7\\
x=log7 \div log 5\\$$

$${\frac{{log}_{10}\left({\mathtt{7}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} = {\mathtt{1.209\: \!061\: \!955\: \!122\: \!167\: \!3}}$$

Guest · Answer 2 · 2015-04-24T04:30:34

^^^Okay, if you're going to be a troll go away. I'm looking for an actual answer to the question. What actually are you doing with your life????