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asdfghjkl help plz iluvyou

math algebra
 Aug 11, 2014

Best Answer 

 #2
avatar+561 
+8

$${\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{yx}}}^{{\mathtt{3}}}\right)}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{yx}}}^{{\mathtt{4}}}\right)}}$$

The 4s cancel out, and the ys cancel out.

=x^3/x^4

The xs cancel out too much, leaving:

=x^-1

But since we can't use negative exponents, we can write it as:

=1/x

Instead.

 Aug 11, 2014
 #1
avatar+128564 
+8

We can divide the "4y"  terms away and are left with ...

x3/x4  =

1/x

And that's it!!

 

 Aug 11, 2014
 #2
avatar+561 
+8
Best Answer

$${\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{yx}}}^{{\mathtt{3}}}\right)}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{yx}}}^{{\mathtt{4}}}\right)}}$$

The 4s cancel out, and the ys cancel out.

=x^3/x^4

The xs cancel out too much, leaving:

=x^-1

But since we can't use negative exponents, we can write it as:

=1/x

Instead.

Will85237 Aug 11, 2014

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