How do you solve this?

Question

0

652

1

+117

$$log 2x + log x^{2}= log 16$$

Namodesto Sep 8, 2014

+128475

+10

Best Answer

log2x + logx² = log 16 using a property of logs on the left hand side

log(2x*x²) = log (16 ) so....equating the expressions in the parentheses, we have

2x³ = 16 divide both sides by 2

x³ = 8 take the cube root of both sides

x = 2

CPhill Sep 8, 2014

CPhill · Answer 1 · 2014-09-08T03:08:17

log2x + logx² = log 16 using a property of logs on the left hand side

log(2x*x²) = log (16 ) so....equating the expressions in the parentheses, we have

2x³ = 16 divide both sides by 2

x³ = 8 take the cube root of both sides

x = 2