How do you solve this?

log x + log (x+3) = 1        write "1" as →  log 10

So we have

log x + log (x + 3) = log (10)    and by a log property, we can write

log [x (x + 3)] = log (10)       and equating the expressions in the brackets and parentheses, we have

x( x + 3)   = 10

X² + 3x - 10 = 0 , and fatoring, we have

(x + 5) ( x - 2)  = 0

So x = -5    or   x = 2

We have to reject the -5 because that gives a negative log in the original problem, and that's undefined.....so.......x = 2

Thank you so much!!