how do your integrate 3x^2

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$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{x}}}^{{\mathtt{2}}}$$

Guest Nov 25, 2014

+128732

+5

Best Answer

∫3 x^2 dx =

3 [x^4 / 4 ] + C =

(3/4)x^4 + C

(If you differentiate this, you will get the function under the integrand, i.e., 3x^2 )

CPhill Nov 25, 2014

CPhill · Answer 1 · 2014-11-25T03:56:13

∫3 x^2 dx =

3 [x^4 / 4 ] + C =

(3/4)x^4 + C

(If you differentiate this, you will get the function under the integrand, i.e., 3x^2 )

MrBalloon · Answer 2 · 2014-11-25T03:52:22

You can't. It is as simplified as possible.