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How does x^5-43x^4+720x^3-5800x^2+22000x-30000 equal (x-10)^4*(x-3)?  My ti-89 graphic calculator gives this answer when I tell it to factor but I do not know how the ti-89 graphic calculator does it.  Anyone who can give me the step-by-step instructions on how to turn x^5-43x^4+720x^3-5800x^2+22000x-30000 to (x-10)^4*(x-3), I would really appreciate it.  Please do not work backwards (going from (x-10)^4*(x-3) to x^5-43x^4+720x^3-5800x^2+22000x-30000).

 May 14, 2015

Best Answer 

 #1
avatar+33616 
+10

As it's a fifth-order polynomial there are 5 roots. Call them a, b, c, d and e (not necessarily all different).

 

 

The polynomial can be written as: (x-a)(x-b)(x-c)(x-d)(x-e) and this must be the same as your polynomial.  Note that if you multiply out the terms in brackets you will end up with the constant term as a*b*c*d*e.

Compare this with the constant term in your polynomial and we see that we must have:

a*b*c*d*e = 30000

 

Now the factors of 30000 are 24*3*54  which we can rewrite as (2*5)4*3 or 104*3.  This is the product of the five numbers 10, 10, 10, 10 and 3, so it's a distinct possibility that we could have a=b=c=d=10 and e=3.

You could then check by multiplying out (x-10)4(x-3) to see if the other terms matched (which they do in this case of course).  If they didn't match you could try making five other integers from   24*3*54 .

 May 14, 2015
 #1
avatar+33616 
+10
Best Answer

As it's a fifth-order polynomial there are 5 roots. Call them a, b, c, d and e (not necessarily all different).

 

 

The polynomial can be written as: (x-a)(x-b)(x-c)(x-d)(x-e) and this must be the same as your polynomial.  Note that if you multiply out the terms in brackets you will end up with the constant term as a*b*c*d*e.

Compare this with the constant term in your polynomial and we see that we must have:

a*b*c*d*e = 30000

 

Now the factors of 30000 are 24*3*54  which we can rewrite as (2*5)4*3 or 104*3.  This is the product of the five numbers 10, 10, 10, 10 and 3, so it's a distinct possibility that we could have a=b=c=d=10 and e=3.

You could then check by multiplying out (x-10)4(x-3) to see if the other terms matched (which they do in this case of course).  If they didn't match you could try making five other integers from   24*3*54 .

Alan May 14, 2015

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