how many 2440x1220 boards wil be needed to cover a 5000x3500 floor
$${\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{3.5}}\right)}{\left({\mathtt{2.44}}{\mathtt{\,\times\,}}{\mathtt{1.22}}\right)}} = {\mathtt{5.878\: \!796\: \!022\: \!574\: \!576\: \!7}}$$
minimum of 6