How many ways are there to put 5 b***s in 2 boxes if the b***s are distinguishable but the boxes are not?
How many ways are there to put 5 b***s in 2 boxes if the b***s are distinguishable but the boxes are not?
B***s different, boxes are the same.
5,0 1ways
4,1 5ways
3,2 5C2 = $${\left({\frac{{\mathtt{5}}{!}}{{\mathtt{2}}{!}{\mathtt{\,\times\,}}({\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{2}}){!}}}\right)} = {\mathtt{10}}$$ ways
16 ways maybe
How many ways are there to put 5 b***s in 2 boxes if the b***s are distinguishable but the boxes are not?
B***s different, boxes are the same.
5,0 1ways
4,1 5ways
3,2 5C2 = $${\left({\frac{{\mathtt{5}}{!}}{{\mathtt{2}}{!}{\mathtt{\,\times\,}}({\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{2}}){!}}}\right)} = {\mathtt{10}}$$ ways
16 ways maybe