+0  
 
0
740
1
avatar

How to simplify the following equation:

10 = x^{1/3}y^{2/3}

My approach was the following:

\frac{10}{x^{1/3}} = y^{2/3}

But how to remove the exponent from y?

 Jul 27, 2015

Best Answer 

 #1
avatar+26367 
+5

$$\begin{array}{rcl}
10 &=& x^{\frac{1}{3}}y^{\frac{2}{3}} \qquad | \qquad 1^3\\\\
10^3 &=& x^{\frac{3}{3}}y^{2\cdot\frac{3}{3}} \\\\
10^3 &=& xy^2 \\\\
xy^2 &=& 10^3 \\\\
xy^2 &=& 10^2\cdot 10 \qquad | \qquad :x \\\\
y^2 &=& 10^2\cdot \dfrac{10}{x} \qquad | \qquad \sqrt{} \\\\
\mathbf{y} & \mathbf{=} & \mathbf{10\cdot \sqrt{ \dfrac{10}{x} }}\\\\
\end{array}$$

.
 Jul 28, 2015
 #1
avatar+26367 
+5
Best Answer

$$\begin{array}{rcl}
10 &=& x^{\frac{1}{3}}y^{\frac{2}{3}} \qquad | \qquad 1^3\\\\
10^3 &=& x^{\frac{3}{3}}y^{2\cdot\frac{3}{3}} \\\\
10^3 &=& xy^2 \\\\
xy^2 &=& 10^3 \\\\
xy^2 &=& 10^2\cdot 10 \qquad | \qquad :x \\\\
y^2 &=& 10^2\cdot \dfrac{10}{x} \qquad | \qquad \sqrt{} \\\\
\mathbf{y} & \mathbf{=} & \mathbf{10\cdot \sqrt{ \dfrac{10}{x} }}\\\\
\end{array}$$

heureka Jul 28, 2015

2 Online Users

avatar