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how to solve fractions with exponent

Guest Apr 25, 2017
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\((\frac47)^{-2}=\frac{4^{-2}}{7^{-2}}=\frac{7^2}{4^2}=\frac{7*7}{4*4}\)

 

 

And...   \(\frac{7*7}{4*4}=\frac{49}{16}\)  :)

hectictar  Apr 25, 2017

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