I have this problem: -3 log5^X +6 is less than or equal to 9 I subtracted 6 on both sides, and then divided by negative 3 on both as well. So now I'm left with log base 5 to the X power is less than or equal to -1... I don't know where to go from here, or if maybe I made a mistake.
That Equation again is: -3 times log base 5 to the power of X, plus 6 which is less than or equal to 9
