Melody can you help me?

Solve the following system:
{3 x+2 y = -12 |     (equation 1)
4 x+5 y = -23 |     (equation 2)
Swap equation 1 with equation 2:
{4 x+5 y = -23 |     (equation 1)
3 x+2 y = -12 |     (equation 2)
Subtract 3/4 × (equation 1) from equation 2:
{4 x+5 y = -23 |     (equation 1)
0 x-(7 y)/4 = 21/4 |     (equation 2)
Multiply equation 2 by 4/7:
{4 x+5 y = -23 |     (equation 1)
0 x-y = 3 |     (equation 2)
Multiply equation 2 by -1:
{4 x+5 y = -23 |     (equation 1)
0 x+y = -3 |     (equation 2)
Subtract 5 × (equation 2) from equation 1:
{4 x+0 y = -8 |     (equation 1)
0 x+y = -3 |     (equation 2)
Divide equation 1 by 4:
{x+0 y = -2 |     (equation 1)
0 x+y = -3 |     (equation 2)
Collect results:
Answer: |  x = -2               and                     y=-3
 

Ya you are

Thank you guest.  Do you understand this answer alright Katie-Leigh ?

It looks like there is a lot of explanation there - thanks Guest.

http://www.cymath.com/answer.php?q=3x%2B2y%3D-12%3B4x%2B5y%3D-23%3Aelimination