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Write 4/27*[2^(3+m/3) + 2^(m/3)]^3 as a power of 2.

Please show all work used :0

Thank you!

 Jan 22, 2017

Best Answer 

 #1
avatar+36916 
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0 mins ago

2^(3+m/3)  =  2^3 * 2^m/3       

so

4/27 ( 2^m/3 ( 2*3 +1) )^3 =

4/27 2^(m/3 *3)(9)^3

4/27 * 2^m 9^3

4/27 * 2^m (3^2)^3

4/3^3  * 2^m * (3^3)^2

4  *   2^m  * 3^3

2^2 * 2^m * 27

2^(2+m) * 27    

 Jan 22, 2017
 #1
avatar+36916 
+5
Best Answer


Guest
0 mins ago

2^(3+m/3)  =  2^3 * 2^m/3       

so

4/27 ( 2^m/3 ( 2*3 +1) )^3 =

4/27 2^(m/3 *3)(9)^3

4/27 * 2^m 9^3

4/27 * 2^m (3^2)^3

4/3^3  * 2^m * (3^3)^2

4  *   2^m  * 3^3

2^2 * 2^m * 27

2^(2+m) * 27    

ElectricPavlov Jan 22, 2017

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