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Prove that the followint is an identity (A is a positive constant).

A*sin(x)*sin(wt)+A*cos(x*)cos(wt)=A*cos(wt-x)

 Jul 26, 2014

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 #1
avatar+128656 
+10

From a trig identity,

cos(Θ) = cos (-Θ)  therefore

cos (wt-x) = cos(-(wt-x)) = cos(x-wt)      so we have ..  (using the angle difference indentity for the cosine)

Acos(x-wt)  = A[cos(x)cos(wt) + sin(x)sin(wt)]  = Asin(x)sin(wt) + Acos(x)cos(wt)    ....and that = the left hand side 

 

  

 Jul 26, 2014
 #1
avatar+128656 
+10
Best Answer

From a trig identity,

cos(Θ) = cos (-Θ)  therefore

cos (wt-x) = cos(-(wt-x)) = cos(x-wt)      so we have ..  (using the angle difference indentity for the cosine)

Acos(x-wt)  = A[cos(x)cos(wt) + sin(x)sin(wt)]  = Asin(x)sin(wt) + Acos(x)cos(wt)    ....and that = the left hand side 

 

  

CPhill Jul 26, 2014

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