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# if (a)^3 + (b)^3 + (c)^3 = 33

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if (a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

Guest Nov 15, 2015

#2
+90996
+5

Thanks guest, that is a great answer.  I just wanted to think about it a little.

There are an infinite number of answers.

(a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

If a=b=c then

$$3*(a^3)=33\\ a^3=11\\ a=\sqrt[3]{11}\\ a=b=c=\sqrt[3]{11}$$

(a)^3 + (b)^3 + (c)^3 = 33

$$a=1,\;\;b=2,\;\;c=\sqrt[3]{24}$$

Melody  Nov 15, 2015
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#1
+5

(33/3)^1/3=2.2239800, the values of a, b, c, because a=b=c

Guest Nov 15, 2015
#2
+90996
+5

Thanks guest, that is a great answer.  I just wanted to think about it a little.

There are an infinite number of answers.

(a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

If a=b=c then

$$3*(a^3)=33\\ a^3=11\\ a=\sqrt[3]{11}\\ a=b=c=\sqrt[3]{11}$$

(a)^3 + (b)^3 + (c)^3 = 33

$$a=1,\;\;b=2,\;\;c=\sqrt[3]{24}$$

Melody  Nov 15, 2015
#3
0

yep, but solve for whole numbers?

Guest Apr 7, 2016

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