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if (a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

Guest Nov 15, 2015

Best Answer 

 #2
avatar+90996 
+5

Thanks guest, that is a great answer.  I just wanted to think about it a little. 

There are an infinite number of answers.

 

(a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

 

If a=b=c then

 

\(3*(a^3)=33\\ a^3=11\\ a=\sqrt[3]{11}\\ a=b=c=\sqrt[3]{11}\)

 

 

Here is another answer.

 

(a)^3 + (b)^3 + (c)^3 = 33

\(a=1,\;\;b=2,\;\;c=\sqrt[3]{24}\)

Melody  Nov 15, 2015
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3+0 Answers

 #1
avatar
+5

(33/3)^1/3=2.2239800, the values of a, b, c, because a=b=c

Guest Nov 15, 2015
 #2
avatar+90996 
+5
Best Answer

Thanks guest, that is a great answer.  I just wanted to think about it a little. 

There are an infinite number of answers.

 

(a)^3 + (b)^3 + (c)^3 = 33

what is a, b and C?

 

If a=b=c then

 

\(3*(a^3)=33\\ a^3=11\\ a=\sqrt[3]{11}\\ a=b=c=\sqrt[3]{11}\)

 

 

Here is another answer.

 

(a)^3 + (b)^3 + (c)^3 = 33

\(a=1,\;\;b=2,\;\;c=\sqrt[3]{24}\)

Melody  Nov 15, 2015
 #3
avatar
0

yep, but solve for whole numbers?

watch: The Uncracked Problem with 33 - Numberphile

Guest Apr 7, 2016

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