If Anna flips 8 coins, what is the probability that she gets more heads than tails?
+250 Gotta be careful with how the question is worded titanium.
Probability of getting more heads than tails in a total of 8 flips is the probability of getting 5 heads, 6 heads, 7 heads, or 8 heads.
Almost identical problem to this: http://web2.0calc.com/questions/a-fair-coin-is-flipped-7-times-what-is-the-probability-that-at-least-5-of-the-flips-come-up-heads
Your final answer should be about 0.363
+2972 mmmmm, probably 1/2 cuz its only heads and tails, so 8 coin flips divided by the 2 sides (in this case, heads and tails)=4 and half of 8 as you know is 4, so the probability overall is 1/2
-Titanium Rome
+250 Gotta be careful with how the question is worded titanium.
Probability of getting more heads than tails in a total of 8 flips is the probability of getting 5 heads, 6 heads, 7 heads, or 8 heads.
Almost identical problem to this: http://web2.0calc.com/questions/a-fair-coin-is-flipped-7-times-what-is-the-probability-that-at-least-5-of-the-flips-come-up-heads
Your final answer should be about 0.363
+355 8C5 + 8C6 + 8C7 + 8C8
56 + 28 + 8 + 1
93
Put it over 256
93/256<-------Answer
93/256 is approximatly 0.363
Using Casework
Case 1:5 heads, 3 tails
8C5 * (1/2)^8 = 7/32
Case 2: 6 heads, 2 tails
8C6 * (1/2)^8 = 7/64
Case 3: 7 heads, 1 tails
8C1 * (1/2)^8 = 1/32
Case 4: All 8 heads
(1/2)^8 = 1/256
7/32 + 7/64 + 1/32 + 1/256 <-------_Add them up
93/256
