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# If f(x)=x^3-7x+5x-9, what is the remainder when f(x) 8is divided by (x+4)?

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If f(x)=x^3-7x+5x-9, what is the remainder when f(x) 8is divided by (x+4)?

Guest Aug 12, 2017
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#1
+78577
+1

I'm assuming that you might mean     x^2 - 7x^2 + 5x  - 9

x^2   - 11x  + 49

x + 4   [  x^3  - 7x^2  + 5x   - 9  ]

x^3  + 4x^2

___________________

-11x^2 +  5x

-11x^2 -   44x

____________

49x - 9

49x + 196

___________

-205

The remainder is -205

Thanks to Alan for pointing out my previous error....!!!!

CPhill  Aug 12, 2017
edited by CPhill  Aug 12, 2017
#2
0

No, I think my question is x^3

Guest Aug 12, 2017
#3
+1362
0

I believe that Cphill meant x^3 - 7x^2 + 5x  - 9 as opposed to x^2- 7x^2 + 5x  - 9.

In case you are wondering, Cphill still calculated the remainder correctly (I did it myself to verify!) despite that writing error.

TheXSquaredFactor  Aug 12, 2017

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