If G(x)=x^2-5x+5, find G'(a) and use it to find equations of the tangent lines to the curve y=x^2-5x+5 at the points (0,5) and (4,1).

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If G(x)=x^2-5x+5, find G'(a) and use it to find equations of the tangent lines to the curve y=x^2-5x+5 at the points (0,5) and (4,1).

G'(a)= I got 2a-5

y1(x)= _____ (passing through (0,5)).

y2(x)=______(passing through (4,1)).

Guest Sep 25, 2016

geno3141 · Answer 1 · 2016-09-25T06:06:42

For the function: G(x) = x² - 5x + 5, G'(x) = 2x - 5

G'(0) = 2(0) - 5 = -5 ---> y₁ - 5 = -5(x - 0) ---> y₁ = -5x + 5

G'(4) = 2(4) - 5 = 3 ---> y₂ - 1 = 3(x - 4) ---> y₂ = 3x - 11

Omi67 · Answer 2 · 2016-09-25T06:33:25

y1(x)= _____ (passing through (0,5)).

y2(x)=______(passing through (4,1)).?