if the half-life of an isotope is 7.6 minutes, how many grams will remain after 12.4 minutes if you started with 80 grams?
We have
40 = 80e^(7.6k) solve for k
divide both sides by 80
.5 = e^(7.6k) take the ln of both sides
ln.5 = lne^(7.6k) and we can write
ln.5 = (7.6k)lne and lne = 1
ln.5 = 7.6k divide both sides by 7.6
ln.5/7.6 = k = about -.0912
So, after 12.4 minutes, we have
80e^(12.4 * -.0912) = about 25.82 g
We have
40 = 80e^(7.6k) solve for k
divide both sides by 80
.5 = e^(7.6k) take the ln of both sides
ln.5 = lne^(7.6k) and we can write
ln.5 = (7.6k)lne and lne = 1
ln.5 = 7.6k divide both sides by 7.6
ln.5/7.6 = k = about -.0912
So, after 12.4 minutes, we have
80e^(12.4 * -.0912) = about 25.82 g