+349 If you saw the first one (a LONG time ago), then you should know the pattern:
\(i=\sqrt{-1}\)
\(i^2=-1\)
\(i^3=-i\)
\(i^4=1\)
Now, try to solve this:
\(i^{2016}+i^{2015}+i^{2014}...+i^2+i\)
This is actually much easier than it looks.
\(36i\)
This is requires you to use the technique:
\(i^{20162015}\)
A little non-imaginary question:
In factoring, can't you just use 2-1 for everything?
Example: Factor x+1 SOLUTION: (x+1)(2-1)? LOL I don't think so (don't get me wrong: I know very well that you cannot use 1 in factoring)
GOOD LUCK AND MAY THE MATHS BE EVER IN YOUR FAVOR 
The title was supposed to be Imaginary Numbers 2...
